Let's skip the fluff. Fractions, decimals, percents, and ratios are really just four different ways of answering the same question: how big is one number compared to another? Once you can flip between them without thinking, a huge chunk of the ISEE quantitative section turns into free points. But first we need to agree on some vocabulary, because the test writers are very picky about their words. The practice is mixed into the lesson: each question sits right after the idea it needs, and the mixed set at the bottom takes that hint away.
Two words show up all over ISEE word problems, and if you mix them up you're toast before you even start computing. The first one is all about multiplying.
The product is the result of multiplying quantities.
Nothing fancy. The only things to watch are the signs and the letters.
Find the product of $-3$ and $5$. Then find the product of $2x$ and $3x$.
Product means multiply, so $(-3)\times 5 = -15$. A negative times a positive is negative. For the second one, multiply the numbers and then multiply the $x$'s: $(2x)(3x) = 6x^2$.
A quotient goes the other direction. Instead of combining things, you're asking how many times one amount fits inside another.
The quotient of $a$ and $b$ is $\dfrac{a}{b}$ (with $b\ne0$); it represents "how many $b$'s fit into $a$."
"Flip and multiply" is the keep, change, flip rule from Section 0: keep the first fraction, change the ÷ to a ×, flip the second.
Here's a quotient of two fractions, which is exactly where that rule earns its keep.
What is the quotient of $\dfrac{3}{4}$ and $\dfrac{1}{8}$?
We're really asking how many eighths fit inside three-quarters. Flip and multiply:
$$\frac{3}{4} \div \frac{1}{8} = \frac{3}{4} \times 8 = 6$$
Sanity check: $\frac{3}{4} = \frac{6}{8}$, which is literally six eighths.
So the words themselves are the easy part. The order they come in is the trap.
Order matters with quotients. "The quotient of $18$ and $6$" is $18 \div 6 = 3$. But "$6$ divided into $18$" is also $18 \div 6 = 3$, even though the $6$ comes first in the sentence. "Divided into" flips the order, and the ISEE loves that phrasing. When you see it, write the division out before you touch a single number.
Sort these phrases before the test sorts you. Drag each one onto the division it means.
Now you translate. Say the operation out loud before you compute anything.
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Every coach who asks for $110\%$ effort is really asking for $1.1$ times your effort. Weirdly specific, but totally legal math.
Percent literally means "per hundred." So $72\%$ is just a fancy way of writing $72$ out of $100$. That makes converting super mechanical: you're always just multiplying or dividing by $100$.
Percent to decimal: divide by $100$, which slides the decimal point two places left.
$$72\% = 72 \div 100 = 0.72$$
Decimal to percent: multiply by $100$, which slides the decimal point two places right.
$$0.39 = 0.39 \times 100\% = 39\%$$
Two hops, every time. Watch the point go, and watch the zeros fill in when it runs out of digits.
Simple, right? This is exactly where the ISEE sets its traps. They know half the room is going to slide the decimal the wrong number of spots.
Which is equivalent to $0.045$? (A) $0.45\%$ (B) $\dfrac{9}{20}$ (C) $\dfrac{9}{200}$ (D) $45\%$
Slide the decimal two places right and you get $4.5\%$, which isn't even a choice! That's your hint to try the fractions. $0.045$ is $45$ thousandths, so
$$0.045 = \frac{45}{1000} = \frac{9}{200}.$$
The answer is (C). Notice that (A) is waiting for the student who only moved the decimal one spot.
Now you guess first, and then the point hops. The two wrong buttons are the two classic slips.
Pick your answer first. Then watch the point hop.
Your turn with the point, both directions.
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Fractions convert the same way. You just have to do the division first to get a decimal.
Convert $\dfrac{7}{8}$ to a percent.
$7 \div 8 = 0.875$, then multiply by $100$ to get $87.5\%$.
That $.5$ is not a mistake, and it's worth knowing cold.
Memorize your eighths. Since $\frac{1}{8} = 12.5\%$, you get $\frac{3}{8} = 37.5\%$, $\frac{5}{8} = 62.5\%$, and $\frac{7}{8} = 87.5\%$. They show up constantly, and knowing them cold saves you a long division problem every single time.
Here's where the eighths come from. On a grid of $100$ squares, one square is $1\%$, so half a square is half a percent, and an eighth of the grid is twelve and a half squares.
Fractions to percents and back, with a grid or a pizza when there's one to count.
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When a problem throws all three forms at you at once, don't try to compare apples to oranges. Pick one language and translate everything into it.
Put $0.31$, $32\%$, and $\dfrac{3}{10}$ in order from least to greatest.
Convert everything to decimals: $\frac{3}{10} = 0.30$, then $0.31$, and $32\% = 0.32$. So the order is $\dfrac{3}{10},\ 0.31,\ 32\%$.
Here are those three landing on one number line, each one translated into a decimal on the way down.
Ordering is always multiple choice, since the choices are the numbers being compared.
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In math word problems, "of" almost always means multiply. "Half of $10$" is $\frac{1}{2} \times 10$. Percents work the exact same way.
Percent Of:
$$p\% \text{ of } n = \frac{p}{100}\cdot n$$
Drag the handle and watch the part grow with the percent. The marks under the bar tell you what each $10\%$ is worth.
The readout under the bar breaks the percent into tens and ones. That's the mental-math move in this example.
What is $28\%$ of $250$?
$\frac{28}{100} \times 250 = 70$. If you don't love multiplying by $28$, break it up instead: $25\%$ of $250$ is $62.5$ and $3\%$ of $250$ is $7.5$, so together you get $70$.
There's more than one good way to break a percent up. Build a few and see which pieces you like.
Now here's a sneaky one. Test-makers use this all the time to reward students who are paying attention.
The Percent Swap:
$$p\% \text{ of } n = n\% \text{ of } p$$
This works because both sides are just $\dfrac{p \cdot n}{100}$.
Here's why, as a block of squares: $8$ rows of $50$ is the same block as $50$ rows of $8$, just turned on its side.
Same squares, so the same answer, and one of the two readings is always easier in your head.
Find $8\%$ of $50$.
$8\%$ of $50$ is annoying to do in your head. But $50\%$ of $8$ is just half of $8$, which is $4$. Same answer, zero work. If the numbers look ugly, flip them.
Percent of a number, with the swap whenever it helps.
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Sometimes they turn the question around and hand you the part instead of the percent. Don't panic, just translate the sentence word by word. Watch it happen.
Here it is on paper, one line per word.
$18$ is what percent of $72$?
"Is" means equals, "what percent" is our unknown $\frac{p}{100}$, and "of" means multiply:
$$18 = \frac{p}{100} \times 72, \quad\text{so}\quad \frac{p}{100} = \frac{18}{72} = \frac{1}{4}, \quad\text{so}\quad p = 25.$$
So $18$ is $25\%$ of $72$.
Part over whole, then times $100$. Try a few.
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The last way to turn it around: they give you the part and the percent, and you need the whole.
$15$ is $20\%$ of what number?
Same translation. "Is" means equals, and the number we want is the whole, $n$:
$$15 = 0.20 \times n, \quad\text{so}\quad n = 15 \div 0.20 = 75.$$
Check it: $20\%$ of $75$ is $15$. Notice the answer is bigger than $15$, which makes sense: $15$ is only a fifth of it.
Here's that backward read as a drag. The part stays put, and you stretch the whole until the part is the right percent of it.
Now find the whole by dividing, no dragging allowed.
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A ratio is just a quotient that we use to compare two piles of stuff side-by-side.
A ratio compares two quantities by division. The ratio of $X$ to $Y$ is written $X:Y$ or $\dfrac{X}{Y}$.
Written as a fraction, a ratio is a quotient, so every fraction fact you know still works. That's what this rule is really saying.
Ratios as Fractions: "Quantity $X$ and Quantity $Y$ have a $3:5$ ratio" means
$$\frac{X}{Y} = \frac{3}{5}.$$
Try one where the ratio is given and one of the counts is known.
$X$ and $Y$ have a $3:5$ ratio. If $X = 21$, what is $Y$?
$\frac{21}{Y} = \frac{3}{5}$, so $Y = 35$. Notice that $21 = 3 \times 7$ and $35 = 5 \times 7$. A $3:5$ ratio doesn't mean there are exactly $3$ and $5$ of anything. It means for every $3$ $X$'s there are $5$ $Y$'s.
Here's where students get burned. There are two flavors of ratio, and the ISEE loves to give you one flavor and then ask a question about the other.
A part-to-part ratio compares one group to another group.
The other flavor compares a group to everything in the pile.
A part-to-whole ratio compares one group to the total number of items.
Same bag of marbles, both flavors.
A bag has $8$ red marbles and $12$ blue marbles. Write the ratio of red to blue, and the ratio of red to all the marbles, in simplest form.
Red to blue is part-to-part: $8:12$. Both divide by $4$, so it's $2:3$.
Red to all is part-to-whole. All the marbles: $8 + 12 = 20$. So it's $8:20$, which divides by $4$ to give $2:5$. Same red marbles, two different ratios, so always check which one the question wants.
Write some ratios of your own. Ratios stay multiple choice, since the answer box only reads numbers.
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Try the mission below, then flip the switch to see the exact same group as a part-to-whole ratio. Hit reset for a new mission (and a new crowd).
See how the simplest form and the percents never budge when you add batches? Only the actual counts change. That hidden multiplier is exactly what we go hunting for in word problems. First, though, the switch in that widget is a skill all by itself: given one flavor, write the other.
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Now the hunt for the multiplier. The giveaway is a part-to-part ratio next to a total.
A school has a boys-to-girls ratio of $6:7$. If there are $390$ students, how many are girls?
Careful: they gave you a part-to-part ratio (boys to girls), but $390$ is the whole. So switch flavors first. Every group of $6 + 7 = 13$ students has $7$ girls, which means girls make up $\frac{7}{13}$ of the school:
$$\frac{7}{13} \times 390 = 7 \times 30 = 210 \text{ girls}$$
Here's that school dealt out one batch of $13$ at a time. The number of batches is the multiplier, and the girls are $7$ per batch.
Same trap, different costume: a mixture is a ratio of ingredients, and the total amount is the whole.
A juice drink is mixed using a concentrate-to-water ratio of $1:9$. How many liters of water are needed to make $7.5$ liters of the drink?
The drink has $1 + 9 = 10$ parts, and $9$ of them are water:
$$\frac{9}{10} \times 7.5 = 6.75 \text{ liters}$$
One more twist. Instead of the total, they give you the gap between the two groups. The multiplier hides in the gap the same way.
A class has boys and girls in the ratio $3:5$. There are $12$ more girls than boys. How many girls are there?
In the ratio, the girls' number is $5 - 3 = 2$ more than the boys'. In real life the gap is $12$. So every ratio number got multiplied by $12 \div 2 = 6$:
$$\text{girls} = 5 \times 6 = 30 \qquad (\text{and boys} = 3 \times 6 = 18,\ \text{a gap of } 12 \text{ as promised})$$
Total or gap, find the multiplier first.
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Sometimes two ratios share a group, and you have to link them up through it. The dogs below are in both ratios, but as different numbers, so the cards get scaled until the dogs match.
The same chain, written out.
At a pet store, the ratio of cats to dogs is $2:3$, and the ratio of dogs to rabbits is $4:5$. What is the ratio of cats to rabbits?
The dogs show up in both, but as a $3$ in one and a $4$ in the other. Make them match: scale the first ratio by $4$ and the second by $3$, so the dogs are $12$ in both.
$$2:3 = 8:12 \qquad 4:5 = 12:15$$
So cats : dogs : rabbits $= 8:12:15$, and cats to rabbits is $8:15$. The trap is just taking the outside numbers, $2:5$.
Now scale the cards yourself. The outside ratio stays locked until the middle numbers agree.
Chain a few on your own.
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When two quantities grow or shrink together at a fixed rate, they track each other through a scaling multiplier. That's all a proportion is.
Two quantities are proportional if one is a constant multiple of the other: $y = kx$.
That multiplier gets a name of its own, because the ISEE asks for it by name.
In $y = kx$, the fixed multiplier $k$ is the constant of proportionality.
Finding $k$ is one division: $k = y \div x$.
If $y = 21$ when $x = 7$, find the constant of proportionality.
$k = \frac{21}{7} = 3$, so $21 = y = kx = 3 \times 7$. And because they're proportional, if $x$ doubled to $14$, then $y$ would double too, to $42$.
Here's a way to picture it. Say every dog at a shelter gets the same number of cookies, $k$. Then the number of cookies is always $k$ times the number of dogs. A lot of students assume "proportional" means "bigger," so keep an eye out for what happens when $k$ drops below $1$.
In Section 5, $k$ gets a new name: the slope of the line $y = kx$. A proportional relationship is just a line with slope $k$ that passes through $(0, 0)$.
Did you catch the graph? Every proportional relationship is a straight line that passes right through the origin, and $k$ controls how steep it is. No dogs means no cookies: if $x$ is $0$, then $y$ has to be $0$ too.
Find $k$ from a pair, a story, or a table.
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And the recognition version: which of these is proportional at all? Remember the test, $y \div x$ is the same for every pair, and $(0, 0)$ is on the line. This one is multiple choice because the choices are the equations and tables themselves.
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Two ratios that are equal make a little equation, and that equation has a name.
A proportion is an equation that says two ratios are equal.
The fastest way to solve almost any proportion is to cross-multiply.
Cross-Multiplication: when $b \ne 0$ and $d \ne 0$,
$$\frac{a}{b} = \frac{c}{d} \iff ad = bc$$
Here's the picture behind it. Multiply both sides by $bd$, and each denominator cancels against one factor, leaving the two diagonal products.
Now the page's own proportion, one cross-multiply and one divide.
Solve the proportion $\dfrac{x}{18} = \dfrac{7}{12}$.
Cross-multiply: $12x = 7 \times 18 = 126$, so $x = 10.5$.
Solve a few. The unknown moves around, but the move is always the same.
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Let's lock this in with a classic scaling problem. Setting up the proportion correctly is $90\%$ of the battle.
Jason and Andrew are building Gym Leader Challenge decks. They pull from a bulk box where the ratio of Grass to Water energy cards is $3:5$. If Jason counts exactly $45$ Grass energy cards in the box, how many Water energy cards are there?
Set up a part-to-part proportion and cross-multiply:
$$\frac{3}{5} = \frac{45}{x}, \quad\text{so}\quad 3x = 225, \quad\text{so}\quad x = 75 \text{ Water cards.}$$
The setup is where the points are lost, so here's the rule for it.
Keep your units lined up. If Grass is on top on the left side, Grass better be on top on the right side too. Most proportion mistakes aren't math mistakes at all, they're just flipped fractions.
Spot the flipped setups. Some of these proportions for the Pokémon problem are fine and some are upside down.
Maps are the same setup with inches and miles.
A map uses a scale of $1$ inch to $12$ miles. Two towns are $3.75$ inches apart on the map. What is the actual distance?
Inches on top, miles on bottom, both sides:
$$\frac{1}{12} = \frac{3.75}{x}, \quad\text{so}\quad x = 12 \times 3.75 = 45 \text{ miles.}$$
Drag the second town and watch the ruler and the proportion keep up.
Recipes, prices, maps, and models: one known pair scales to a new one.
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Speed is a proportion too: the miles grow at a fixed rate per hour. Rates, unit rates, and the ISEE's favorite twist (a time given in hours and minutes) get their own treatment in Section 4.
Percent change measures how much something moved compared to where it started. Hang on to that word "started," because it's the whole game here.
Percent Change:
$$\%\text{ Change} = \frac{\text{New} - \text{Original}}{\text{Original}} \times 100\%$$
Here's the classic, with the trap baked right into the numbers.
A realtor buys a house for $\$800{,}000$ and wants to make a $\$200{,}000$ profit. By what percent should the selling price exceed the purchase price?
The change is the $\$200{,}000$ profit, and the original is what she paid:
$$\frac{200{,}000}{800{,}000} \times 100\% = 25\%$$
The trap answer is $20\%$, which is what you get if you divide by the $\$1{,}000{,}000$ selling price instead. Always divide by the original.
Stack copies of the change inside each bar. Four fit in the start, five fit in the end, and only one of those is the percent change.
Change over original, times $100$. Up or down, same formula.
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Here's a nasty cousin of that trap: one gap, two different percents, depending on which end you measure from.
Store A's price for a game is $60\%$ more than Store B's. Store B's price is what percent less than Store A's?
Pick a friendly number for the smaller one. Say Store B charges $\$100$; then Store A charges $\$160$. The gap is $\$60$ either way, but "less than Store A's" means we measure from Store A's $\$160$:
$$\frac{60}{160} = 0.375 = 37.5\%$$
So Store B's price is $37.5\%$ less, not $60\%$ less. The $60$ was measured from the smaller price; the $37.5$ is measured from the bigger one.
Same trick every time: call the smaller amount $100$, build the other, and divide the gap by the right one.
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When you just want the new amount, skip the middle step and use a multiplier. Going up? Multiply by a little more than $1$. Going down? A little less than $1$.
A $p\%$ increase: $\text{New} = \text{Original} \times \left(1 + \dfrac{p}{100}\right)$
A $p\%$ decrease: $\text{New} = \text{Original} \times \left(1 - \dfrac{p}{100}\right)$
One change, one multiplier.
A town has $2{,}400$ people. Over the year its population grows by $15\%$. How many people does it have now?
Up $15\%$ means multiply by $1.15$:
$$2{,}400 \times 1.15 = 2{,}760 \text{ people}$$
Or in two steps: $15\%$ of $2{,}400$ is $360$, and $2{,}400 + 360 = 2{,}760$. The multiplier just does both steps at once.
Sales, markups, tips, and towns that grow.
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Two changes in a row just means two multipliers, each one applied to whatever's there at the time.
An $\$80$ item is discounted by $25\%$, and then an $8\%$ sales tax is applied to the discounted price. What is the final price?
Discount first: $80 \times 0.75 = 60$. Then tax on that: $60 \times 1.08 = 64.80$. The final price is $\$64.80$. The tax gets charged on the discounted price, not the original.
Watch the bar shrink and then grow a little back.
Sometimes they hand you the price after the change and ask where it started. Work backward with the same multiplier.
After a $20\%$ discount, a coat costs $\$64$. What was the original price?
A $20\%$ discount leaves $80\%$ of the price, so the original price times $0.80$ is $64$:
$$\text{Original} \times 0.80 = 64, \quad\text{so}\quad \text{Original} = 64 \div 0.80 = \$80.$$
The trap is adding $20\%$ back on: $64 \times 1.20 = \$76.80$. That's $20\%$ of the sale price, but the discount was $20\%$ of the original.
Guess first, then watch the bar model settle it.
Guess the original price before the bars show up.
Divide by the multiplier. Never add the percent back on.
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Now here's the trap that gets almost everyone the first time. The widget below starts on $+50\%$ then $-50\%$. Where do you think you end up?
Make your guess before the last bar shows up. Then try the other classic traps.
Here's the same idea with numbers that look like they should cancel and don't.
The price of a computer rises by $25\%$ and then falls by $20\%$. Compared to the original price, the final price is what?
Your gut says "up $5\%$." Your gut is wrong. Chain the multipliers:
$$1.25 \times 0.80 = 1.00$$
The final price is exactly equal to the original.
Up a quarter, then down a fifth, and the bar lands right back on the starting line.
So why does everybody's gut get this wrong? Because the second percent is taken of a different number.
Percent changes multiply, they don't add. A $50\%$ increase followed by a $50\%$ decrease is not a wash: $12{,}000 \to 18{,}000 \to 9{,}000$, which is a $25\%$ drop overall. Any time you see two percent changes in a row, reach for multipliers.
Multipliers, chained. Sale then tax, markup then sale, up then down.
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The ISEE has a question type you won't see on most tests: two columns, and you decide which one is bigger. The four choices never change. (A) Column A is greater, (B) Column B is greater, (C) the two are equal, or (D) the relationship can't be determined from the information given. That last one is the trap door, so check it every single time.
Let $x$ be a number.
Try a few values of $x$. If $x = 6$, Column A is $3$ and Column B is $2$, so A wins. If $x = 0$, both columns are $0$. If $x = -6$, Column A is $-3$ and Column B is $-2$, so now B wins. Different values give different winners, so the answer is (D), it can't be determined.
If the problem had said "$x$ is a positive number," the answer would be (A). One little word changes everything.
Here are those three values run through both columns. The winner flips, and that flip is the whole answer.
Now you pick the values. Plug in a few and watch for a flip, or for the columns to lock together.
Every question so far came right after its idea, which is a hint the real test never gives. Down here the hint is gone. First, the quantitative comparison: two columns, four fixed choices, and any idea from this section fair game.
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Next, the mixed set. Every question type on this page except the quantitative comparison goes into one hat, and each click draws a new one at random. Flip the switch to type your answer (fractions like 5/8 and percents like 37.5 are fine); a few types need their answer choices, and they'll say so.
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Alright, if you've made it this far, it's time for something with a little heat. These are multi-step problems where you have to chain together everything from this section. Don't rush them. Write down what each ratio is comparing before you do any math.
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